Tracing Wood-armer combinations into Report page

SOFiSTiK Teddy
,
1

Hey,

How can I trace my wood-armer combinations into report page?

Workflow goes:

!#!Chapter 7 LINEAR ANALYSIS BASELINE
+PROG ASE urs:8$ LINEAR ANALYSIS
HEAD Linear Analysis Baseline
ECHO DISP,REAC,LOAD,GRP NO ; ECHO FORC YES
GRP - FULL
LC NO ALL
END

!#!Chapter 8 LINEAR SUPERPOSITION ENVELOPES
+PROG MAXIMA urs:9
HEAD ULS ENVELOPE GENERATION
CTRL

#define supp
supp extr mami etyp node type p,UX,UY,UZ Titl “Result $(base)”
supp extr mami etyp quad type Vx,vy,m,n Titl “Result $(base)”
supp extr mami etyp beam type N,Vy,Vz,Mt,My,Mz Titl “Result $(base)”
supp extr mami etyp spri type p,m,u Titl “Result $(base)”
supp extr mami etyp auto type vx,vy,vz
#enddef

#define base=50000
COMB 5 EXTR DESI TYPE DESI TITL “Tulos $(base)” BASE $(base)
ACT G_1
ACT G_2
ACT Q
ACT Q_1
ACT Q_2
$ACT QT_1
$ACT QT_2
$ACT QT_3
$ACT Q_4
$ACT Q_5
#include supp
echo chck

#define base=60000
$ SLS DESIGN ACCORDING TO ACT. DEFINE EXTR chracteristic - Käyttörajatila
COMB 6 EXTR rare TYPE none TITL “Tulos $(base)” BASE $(base)
ACT G_1
ACT G_2
ACT Q
ACT Q_1
ACT Q_2
$ACT QT_1
$ACT QT_2
$ACT QT_3
$ACT Q_4
$ACT Q_5
$add {G} facu 1 facf 1
$ ada G
$add {Q} facu psi0 facf 1
$ ada Q

#include supp

#define base=70000
$ SLS DESIGN ACCORDING TO ACT. DEFINE EXTR EXTR frequent-> Usein toistuva
COMB 7 EXTR freq TYPE none TITL “Tulos $(base)” BASE $(base)
ACT G_1
ACT G_2
ACT Q
ACT Q_1
ACT Q_2
$ACT QT_1
$ACT QT_2
$ACT QT_3
$$ACT Q_4
$$ACT Q_5
$$add {G} facu 1 facf 1
$$ ada G
$$add {Q} facu psi0 facf 1
$$ ada Q

#include supp

#define base=80000
$ SLS DESIGN ACCORDING TO ACT. DEFINE EXTR quasi-permanent - Pitkäaikaisyhdistelmä
COMB 8 EXTR perm TYPE none TITL “Tulos $(base)” BASE $(base)
ACT G_1
ACT G_2
ACT Q
ACT Q_1
ACT Q_2
$ACT QT_1
$ACT QT_2
$ACT QT_3
$$ACT Q_4
$$ACT Q_5
$$add {G} facu 1 facf 1
$$ ada G
$$add {Q} facu psi0 facf 1
$$ ada Q

#include supp

END

+prog bemess urs:8
head
ctrl dmom 5000
lc (50001 50010 1)
end

+prog bemess urs:10
head
ctrl dmom 5000
lc (60001 60010 1)
end

+prog bemess urs:11
head
ctrl dmom 5000
lc (70001 70010 1)
end

+prog bemess urs:12
head
ctrl dmom 5000
lc (80001 80010 1)
end

!#!Chapter 9 TRACING COMBINATIONS
+prog maxima urs:6
head TRACING OF COMPBINATIONS

trac lc 60073 etyp node elem 2487
trac lc 60073 etyp node elem 1707

trac lc 50045 etyp spri elem 8028

trac lc 50022 etyp beam elem 1145 x 0.0
trac lc 50022 etyp beam elem 1160 x 0.5285

trac lc 50021 etyp beam elem 1145 x 0.0
trac lc 50021 etyp beam elem 1160 x 0.5285

$trac lc 55004 etyp node elem 3722

end

2

Hello,

as I understand your question regarding the wood-armer combinations you want to have the resultant load case combinations in the printout.

MAXIMA uses action combinations which are given in the corresponding design codes (EN 1990 and its National Annexes) and determines the resultant load case combinations. The resultant load case combinations depend on the superposition value (e.g. for beams My,Vz) and the position in the structure (e.g. middle of span or support). This means that many load case combinations can result for a structure.

The record TRAC in an own MAXIMA run can show the resultant load case combination for a specific superposition value at a specific position .

If the most relevant load case combination and / or its position in the structure is not known, we recommend to use the following printout in MAXIMA during superposition:
ECHO CHCK prints the most unfavourable result with the used initial load case and their determined factors as well as the position in the structure. This information can be used for the tracer.

If you want an overview of all determined load case combinations in MAXIMA, you can use ECHO SUM which prints all determined load case combinations with information about the corresponding superposition value.

With kind regards
Sabine Fahrendholz
Senior Product Mana ger

3

Thank you, I think I can clarify my question.

For a reinforced concrete slab, I want to find the governing bending moment Mxx for reinforcement design, including the effect of torsion Mxy.

If I simply take MAX Mxx from MAXIMA, this gives me the maximum Mxx, but it may occur in a different load combination than the maximum Mxy.

So my question is:

What is the correct way in MAXIMA to obtain the governing Mxx design value while taking the simultaneous torsional moment Mxy into account?