Direction of transverse springs

I’m struggling with understanding the transverse direction of springs.

I have a 2D longitudinal model, made in a 3D system (in order to use axes).
When I define a spring with the main direction along the longitudinal axis, I want the transverse direction to be in the vertical direction.

However, when defining the spring, the transverse is in the perpendicular horizontal direction to the main direction, and I see no means of rotating the spring.

Please see the attached snippet below with the wished transverse direction shown with a red arrow.

+Prog SOFIMSHC urs:2 $ Geometry
SYST 3D GDIV 100 GDIR NEGZ
ctrl mesh 1
SPT 1 X 0 Y 0 Z 0
SPT 2 X 1 Y 0 Z 0
spts no 3 ref 1 CQ 10 CP 100 CRAC 0.0 grp 1 type C DX 1 DY 0 DZ 0
end 

Hi MRCH,

as you can see in the manual, the transverse spring direction is a plane perpendicular to the axial direction:

The first parameter CA describes an axial stiffness along the principal direction of the spring. The second parameter CQ describes a stiffness component acting in the whole plane perpendicular to the axial direction.

In your case you need to define 2 single springs, both with a value CP:
spts … CP 100 DX 1 DY 0 DZ 0
spts … CP 10 DX 0 DY 0 DZ 1

Birgit

Hi Birgit

Thank you very much for your reply, I had a feeling that was the issue as well.

In your example, would there be any difference in writing:

spts … CP 100 CQ 10 DX 1 DY 0 DZ 0

instead of:

spts … CP 100 DX 1 DY 0 DZ 0
spts … CP 10 DX 0 DY 0 DZ 1

The reason I’m asking is that in my main model which I’ve tried to summarize in the previous model, I see a vertical spring force in springs which have no transverse stiffness assigned. Please see the figure below:

The definition of the springs is seen below:

spt 361 ref pt 25501 z -8.25 mref ax 'ax'
sptp type 'f' ref 25501 grp 255
    spts no 361 ref 358 CQ 0.0 CP 100000000.0 CRAC 0.0 grp 255
spt 362 ref pt 25501 z -4.43 mref ax 'ax'
sptp type 'f' ref 25501 grp 255
    spts no 362 ref 359 CQ 25000000.0 CP 0.0 CRAC 1e+99 grp 255
spt 363 ref pt 25501 z -0.61 mref ax 'ax'
sptp type 'f' ref 25501 grp 255
    spts no 363 ref 360 CQ 0.0 CP 100000000.0 CRAC 0.0 grp 255 

In my example there is no spring that contains a value for CQ, because that would be a spring in an undefined direction (plate - see manual).

It is important that you define a spring for each direction with a value for CP and an associated direction (DX, DY, DZ).

One can’t say more without a system.