Interpolation Section Teddy TVAR

Hi Nathan,

you defined the two structural lines with reference on axis LTR1/LTR2. So you have to add the GAXV command for these two axes:

GAX LTR1 TYPE LANE TYPC NURB DEGR 1
GAXN S 0.00000000
GAXN S 14.00000000
GAXN S 42.33041780
GAXN S 56.33040559
GAXC X -0.35503268 1.32500000 -0.08000000
GAXC X 13.64496732 1.32500000 -0.08000000
GAXC X 41.90862293 -0.61879633 -0.08000000
GAXC X 55.77164688 -2.57231247 -0.08000000

GAXP LTR1 S 0 TYPE ‘A’
GAXP LTR1 S 56.330405591823066 TYPE ‘E’

GAXV LTR1 NAME ‘StegHH’ S 0 V 1250
GAXV LTR1 NAME ‘StegHH’ S 11.9 V 1250
GAXV LTR1 NAME ‘StegHH’ S 14 V 1250
GAXV LTR1 NAME ‘StegHH’ S 18.2 V 1250
GAXV LTR1 NAME ‘StegHH’ S 35 V 900
GAXV LTR1 NAME ‘StegHH’ S 37.8 V 1250
GAXV LTR1 NAME ‘StegHH’ S 42 V 1250
GAXV LTR1 NAME ‘StegHH’ S 44.099999999999994 V 1250
GAXV LTR1 NAME ‘StegHH’ S 56 V 1250

GAX LTR2 TYPE LANE TYPC NURB DEGR 1
GAXN S 0.00000000
GAXN S 14.00008507
GAXN S 41.62389498
GAXN S 55.62389498
GAXC X 0.35503268 -1.32500000 -0.08000000
GAXC X 14.35511775 -1.32531748 -0.08000000
GAXC X 41.90862293 -3.29489265 -0.08000000
GAXC X 55.77164688 -5.24849626 -0.08000000

GAXP LTR2 S 0 TYPE ‘A’
GAXP LTR2 S 55.62389498446986 TYPE ‘E’

GAXV LTR2 NAME ‘StegHH’ S 0 V 1250
GAXV LTR2 NAME ‘StegHH’ S 11.9 V 1250
GAXV LTR2 NAME ‘StegHH’ S 14 V 1250
GAXV LTR2 NAME ‘StegHH’ S 18.2 V 1250
GAXV LTR2 NAME ‘StegHH’ S 35 V 900
GAXV LTR2 NAME ‘StegHH’ S 37.8 V 1250
GAXV LTR2 NAME ‘StegHH’ S 42 V 1250
GAXV LTR2 NAME ‘StegHH’ S 44.099999999999994 V 1250
GAXV LTR2 NAME ‘StegHH’ S 56 V 1250

Best regards,
Nora

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