ELLA Traffic loader and LM3

1

Hello
I am trying to use ELLA to apply traffic loads to a bridge, but when adding my LM3 i dont see any loadtrain that corresponds to the actual code.

These are the loadtrains i can choose from:

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image338×318 3 KB

According to the code, this a class 150 vehicle.
image

When applying LM3 900 150, i only get values of 75 for all wheels.

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image1601×836 78.5 KB

I looked in the manual, but i dont understand the purpose of adding loadtrains that does not correspond to the predefined ones in the code?

2

Hi,

Actually, the load model you selected, “LM3 900 150”, is a load system composed of 6 axles of 150 kN each (6 × 150 = 900 kN).

In your case, with the load you’ve defined, it’s not necessarily listed in the ELLA catalogue. If that’s the case, you can define it manually using TEDDY with the “TRPL” record (Point Load of Load Train).

Here is an example:

LC NO 1204 TYPE NONE TITL 'P.E.B. LECLERC'
TRAI    USER    WIDT    3.00  PFAC 1.0  PHI     1.05    PHIS    1.05  DIR B   
TRPL    P   PB  PW  PF  DIST    A   DPOS    DMIN    DMAX    Y   HW  ZW  HF  PHI B   BW  LW
    98.55   0   0   0   min 25  0   0   0   0   0   0   0   1   2.189   0.31    0.3
    128.975 0   0   0   ABS 4.325   0   0   0   0   0   0   0   1   2.05    0.75    0.3
    128.975 0   0   0   ABS 1.35    0   0   0   0   0   0   0   1   2.05    0.75    0.3
    103.16  0   0   0   ABS 5.635   0   0   0   0   0   0   0   1   2.652   0.535   0.2
    103.17  0   0   0   ABS 1.36    0   0   0   0   0   0   0   1   2.652   0.535   0.2
    103.17  0   0   0   ABS 1.36    0   0   0   0   0   0   0   1   2.652   0.535   0.2
    103.17  0   0   0   ABS 1.36    0   0   0   0   0   0   0   1   2.652   0.535   0.2
    103.17  0   0   0   ABS 1.36    0   0   0   0   0   0   0   1   2.652   0.535   0.2
    103.16  0   0   0   ABS 1.36    0   0   0   0   0   0   0   1   2.652   0.535   0.2

Just one question: which standard or code is your load based on? Because LM3 is country-specific.

Good luck,
Abderrahman OMRI

3

Hello.
Thank you, i figured it out with your input.
I am using Eurocodes, danish annexes.

Although i am still not sure i understand the input syntax. I am defining my load values, but when tracing the loadpositions, random values seems to be used for the load train.

When seen in winGRAF:

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image1057×421 4.69 KB

These are the values generated from this code, see the last 7 load values. I have added a value of 50, which shows up as two values of 18,7 kN.

LC 1211 TYPE NONE TITL 'kl.150'
    TRAI USER WIDT 3[m]
    TRPL P 68.6  BW 0.6[m] LW 0.2[m] NW 2 B 2[m]
    TRPL P 68.6 BW 0.6[m] LW 0.2[m] NW 2 B 2[m] A -1.4[m]
    TRPL P 93.2 BW 0.6[m] LW 0.2[m] NW 2 B 2[m] A -3.2[m]
    TRPL P 93.2 BW 0.6[m] LW 0.2[m] NW 2 B 2[m] A -1.4[m]
    TRPL P 174.6 BW 0.6[m] LW 0.2[m] NW 2 B 2[m] A -6[m]
    TRPL P 174.6 BW 0.6[m] LW 0.2[m] NW 2 B 2[m] A -1.4[m]
    TRPL P 50    BW 0.6[m] LW 0.2[m] NW 2 B 2[m] A -1.4[m]
    TRPL P 174.6 BW 0.6[m] LW 0.2[m] NW 2 B 2[m] A -1.4[m]
    TRPL P 174.6 BW 0.6[m] LW 0.2[m] NW 2 B 2[m] A -1.4[m]
    TRPL P 174.6 BW 0.6[m] LW 0.2[m] NW 2 B 2[m] A -1.4[m]
    TRPL P 174.6 BW 0.6[m] LW 0.2[m] NW 2 B 2[m] A -1.4[m]
4

I found the solution.
Using action GR_5 for the group will return characteristic values.

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