BEMEES Shift Rule

SOFiSTiK Teddy
1

Hello,

Does anyone knows how sofistik calculates the additional normal force when SHFT is enabled?

Thank you.
Andrei

2

Hello Andrei,

the calculation of the additional normal force is described in the Eurocode 2 (DIN EN 1992-1-1) chapter 9.2.1.3. Furthermore you can look at the TEDDY example within the BEMESS manual.

Help > manuals > all manuals … > bemess > 3.7 SHFT > Example versatz.dat

The only problem is that the example is only available in German. You can translate the commands by right-clicking on “Deu” and on “CADINP übersetzen” in the bottom right corner of the program.

Best regards,
Frederik Höller
Your SOFiSTiK Support Team

3

There is actually an english version already under:

C:\Program Files\SOFiSTiK\2020\SOFiSTiK 2020\bemess.dat\english\special\shift_rule.dat

Are you sure that the additional tensile reinforcement is calculated with an actual shift?

I thought the additional tensile force was calculated with expression 6.18 in 1992-1-1 as in aqb, see:

https://forum.sofistik.de/t/longitudinal-tensile-force-from-shear/270/2https://forum.sofistik.de/t/longitudinal-tensile-force-from-shear/270/2

Would be interesting to know if the additional normal force is applied as half of the shear on the reinforcement or as the total shear on the entire section. (if that’s how it is done)

/Stefan

4

Hello,

Thank you for your reply. I found the Teddy example. The results are below. We can see that the curve was shifted, but the tension is not limited at MEd,max/z like EC2 says.

There is a way to limit the force on the support at Med,max/z ?

shift
shift1982×749 147 KB

Best regards,
Andrei